GPT 当前会话桥接(流程验收)
openai_compatible · json_schema综合得分 / 100 · 越高越好RUN / #0016完成但有错误
模型:GPT 当前会话桥接(流程验收)。比较模式:single_model;差异字段:无。创建于 2026年8月29日 22:05。
非全量成功 · 本场包含 2 个失败案例失败已经按固定规则计入综合得分,具体影响可在逐题表和案例证据中复核。
openai_compatible · json_schema综合得分 / 100 · 越高越好分别列出准确率、每正确等价题 Token、估算费用和生成耗时。费用采用运行时冻结的价格快照。
| 指标 | GPT 当前会话桥接(流程验收) |
|---|---|
准确率越高越好 | 87.31 |
Token / 正确等价题越低越好 | 2,953 |
费用 / 正确等价题USD · 估算 | 不可估算 |
模型生成耗时 P95越低越好 | — |
累计 Token已记录题数 | 46,41517/18 题 |
| 能力维度 | GPT 当前会话桥接(流程验收) |
|---|---|
| 基础查询 | 100.00 |
| 复杂查询 | 96.38 |
| 数据开发 | 92.50 |
| 时间与窗口 | 68.33 |
| 聚合与指标 | 100.00 |
| 连接与粒度 | 66.67 |
展开案例可查看模型摘要、SQL、错误和原始案例 JSON。
| 案例 | GPT 当前会话桥接(流程验收) |
|---|---|
基础筛选与排序basic_filter_sort | 100.00 |
多表连接品类收入multi_join_category_revenue | 100.00 |
保留零订单客户left_join_zero_orders | 100.00 |
相关子查询分群均值correlated_segment_average | 100.00 |
从未完成订单客户not_exists_customers | 100.00 |
每品类收入前三商品top3_products_per_category | 100.00 |
月收入与累计收入monthly_running_revenue | 100.00 |
月收入环比增长monthly_mom_growth | 5.00 |
高于平均累计消费客户above_average_customer_spend | 89.15 |
渠道支付状态金额payment_status_by_channel | 100.00 |
品类退货率category_return_rate | 92.50 |
每单最新成功支付latest_successful_payment | 85.00 |
缺失城市标准化null_city_label | 100.00 |
已完成订单金额分层completed_order_amount_band | 100.00 |
全渠道经营表现all_channel_performance | 0.00 |
渠道核心指标semantic_channel_kpis | 100.00 |
品类收入贡献占比category_revenue_share | 100.00 |
订单头明细金额对账order_total_reconciliation | 100.00 |
basic_filter_sort筛选 2026-01-01 起的已完成订单,连接客户维表获取客户名称,输出订单字段并按金额降序、订单号升序排列。
SELECT
o.order_id,
c.customer_name,
o.order_date,
o.total_amount
FROM fact_orders AS o
JOIN dim_customers AS c
ON o.customer_id = c.customer_id
WHERE
o.status = 'completed' AND o.order_date >= CAST('2026-01-01' AS DATE)
ORDER BY
o.total_amount DESC,
o.order_id ASCcompletedGEN—msEXEC430.8156249971944msmulti_join_category_revenue连接订单、订单行和商品表,筛选已完成订单后按品类统计 distinct 订单数与订单行净销售额,并按指定顺序排序。
SELECT
p.category,
COUNT(DISTINCT o.order_id) AS order_count,
SUM(oi.quantity * oi.unit_price - oi.discount_amount) AS net_revenue
FROM fact_orders AS o
JOIN fact_order_items AS oi
ON oi.order_id = o.order_id
JOIN dim_products AS p
ON p.product_id = oi.product_id
WHERE
o.status = 'completed'
GROUP BY
p.category
ORDER BY
net_revenue DESC,
p.category ASCcompletedGEN—msEXEC251.31245899683563msleft_join_zero_orders以客户表为主表 LEFT JOIN 订单表,通过条件去重计数统计已完成订单,保留零订单客户并按指定顺序排序。
SELECT
c.customer_id,
c.customer_name,
COUNT(DISTINCT CASE WHEN o.status = 'completed' THEN o.order_id END) AS completed_order_count
FROM dim_customers AS c
LEFT JOIN fact_orders AS o
ON o.customer_id = c.customer_id
GROUP BY
c.customer_id,
c.customer_name
ORDER BY
completed_order_count DESC,
c.customer_id ASCcompletedGEN—msEXEC215.4034999985015mscorrelated_segment_average连接已完成订单与客户,并通过引用外层客户分群的相关子查询计算该分群已完成订单平均金额,再筛选高于均值的订单并按要求排序。
SELECT
ranked_orders.order_id,
ranked_orders.customer_id,
ranked_orders.segment,
ranked_orders.total_amount,
ranked_orders.segment_avg_amount
FROM (
SELECT
o.order_id,
o.customer_id,
c.segment,
o.total_amount,
(
SELECT
AVG(o2.total_amount)
FROM fact_orders AS o2
JOIN dim_customers AS c2
ON o2.customer_id = c2.customer_id
WHERE
o2.status = 'completed' AND c2.segment = c.segment
) AS segment_avg_amount
FROM fact_orders AS o
JOIN dim_customers AS c
ON o.customer_id = c.customer_id
WHERE
o.status = 'completed'
) AS ranked_orders
WHERE
ranked_orders.total_amount > ranked_orders.segment_avg_amount
ORDER BY
ranked_orders.total_amount DESC,
ranked_orders.order_id ASCcompletedGEN—msEXEC251.31962500017835msnot_exists_customers从客户主表出发,使用相关 NOT EXISTS 子查询排除任何存在已完成订单的客户,并按 customer_id 升序输出。
SELECT
c.customer_id,
c.customer_name
FROM dim_customers AS c
WHERE
NOT EXISTS(
SELECT
1
FROM fact_orders AS o
WHERE
o.customer_id = c.customer_id AND o.status = 'completed'
)
ORDER BY
c.customer_id ASCcompletedGEN—msEXEC269.77720799914096mstop3_products_per_category先汇总完成订单中各品类商品的净销售额,再用 ROW_NUMBER 按品类分区排名并取前三。
WITH product_revenue AS (
SELECT
p.category,
p.product_id,
p.product_name,
SUM(oi.quantity * oi.unit_price - oi.discount_amount) AS net_revenue
FROM fact_order_items AS oi
INNER JOIN fact_orders AS o
ON oi.order_id = o.order_id
INNER JOIN dim_products AS p
ON oi.product_id = p.product_id
WHERE
o.status = 'completed'
GROUP BY
p.category,
p.product_id,
p.product_name
), ranked_products AS (
SELECT
category,
product_id,
product_name,
net_revenue,
ROW_NUMBER() OVER (PARTITION BY category ORDER BY net_revenue DESC, product_id ASC) AS rank_no
FROM product_revenue
)
SELECT
category,
product_id,
product_name,
net_revenue,
rank_no
FROM ranked_products
WHERE
rank_no <= 3
ORDER BY
category ASC,
rank_no ASCcompletedGEN—msEXEC213.90308300033212msmonthly_running_revenue按 2025 年月份汇总已完成订单商品行净销售额,并使用按 month 排序的 SUM 窗口计算累计收入。
WITH monthly AS (
SELECT
STRFTIME(o.order_date, '%Y-%m') AS month,
SUM(oi.quantity * oi.unit_price - oi.discount_amount) AS monthly_revenue
FROM fact_orders AS o
INNER JOIN fact_order_items AS oi
ON oi.order_id = o.order_id
WHERE
o.status = 'completed'
AND o.order_date >= CAST('2025-01-01' AS DATE)
AND o.order_date < CAST('2026-01-01' AS DATE)
GROUP BY
STRFTIME(o.order_date, '%Y-%m')
)
SELECT
month,
monthly_revenue,
SUM(monthly_revenue) OVER (ORDER BY month ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS cumulative_revenue
FROM monthly
ORDER BY
month ASCcompletedGEN—msEXEC233.4604159987066msmonthly_mom_growthabove_average_customer_spend先汇总每位有已完成订单客户的订单行净销售额,再通过外层派生表计算客户平均累计消费,筛出高于平均值者并按指定顺序输出。
SELECT
customer_id,
customer_name,
total_spend
FROM (
SELECT
customer_spend.customer_id,
customer_spend.customer_name,
customer_spend.total_spend,
AVG(customer_spend.total_spend) OVER () AS avg_total_spend
FROM (
SELECT
c.customer_id,
c.customer_name,
SUM(
COALESCE(oi.quantity * oi.unit_price - oi.discount_amount, CAST(0 AS DECIMAL(14, 2)))
) AS total_spend
FROM fact_orders AS o
INNER JOIN dim_customers AS c
ON o.customer_id = c.customer_id
LEFT JOIN fact_order_items AS oi
ON o.order_id = oi.order_id
WHERE
o.status = 'completed'
GROUP BY
c.customer_id,
c.customer_name
) AS customer_spend
) AS customer_spend_with_average
WHERE
total_spend > avg_total_spend
ORDER BY
total_spend DESC,
customer_id ASCcompletedGEN—msEXEC305.6103749986505mspayment_status_by_channel将支付记录经订单关联到渠道,按渠道类型分组,并使用三组 SUM(CASE WHEN ...) 分别汇总 paid、refunded 和 failed 状态金额。
SELECT
c.channel_type,
SUM(CASE WHEN p.status = 'paid' THEN p.amount ELSE 0 END) AS paid_amount,
SUM(CASE WHEN p.status = 'refunded' THEN p.amount ELSE 0 END) AS refunded_amount,
SUM(CASE WHEN p.status = 'failed' THEN p.amount ELSE 0 END) AS failed_amount
FROM fact_payments AS p
JOIN fact_orders AS o
ON p.order_id = o.order_id
JOIN dim_channels AS c
ON o.channel_id = c.channel_id
GROUP BY
c.channel_type
ORDER BY
c.channel_type ASCcompletedGEN—msEXEC201.53850000497187mscategory_return_rate分别在品类粒度聚合已完成订单的售出数量与退货数量,再连接聚合结果计算四舍五入至 4 位的退货率,避免明细连接导致 fan-out。
WITH sold_by_category AS (
SELECT
p.category,
SUM(oi.quantity) AS sold_qty
FROM fact_orders AS o
INNER JOIN fact_order_items AS oi
ON o.order_id = oi.order_id
INNER JOIN dim_products AS p
ON oi.product_id = p.product_id
WHERE
o.status = 'completed'
GROUP BY
p.category
), returned_by_category AS (
SELECT
p.category,
SUM(r.return_qty) AS returned_qty
FROM fact_returns AS r
INNER JOIN fact_order_items AS oi
ON r.order_id = oi.order_id AND r.line_no = oi.line_no
INNER JOIN fact_orders AS o
ON oi.order_id = o.order_id
INNER JOIN dim_products AS p
ON oi.product_id = p.product_id
WHERE
o.status = 'completed'
GROUP BY
p.category
)
SELECT
s.category,
s.sold_qty,
COALESCE(r.returned_qty, 0) AS returned_qty,
ROUND(CAST(COALESCE(r.returned_qty, 0) AS DECIMAL(38, 10)) / NULLIF(s.sold_qty, 0), 4) AS return_rate
FROM sold_by_category AS s
LEFT JOIN returned_by_category AS r
ON s.category = r.category
ORDER BY
return_rate DESC,
s.category ASCcompletedGEN—msEXEC240.50150000402937mslatest_successful_payment从成功支付记录中使用 ROW_NUMBER 为每个订单按支付时间及 payment_id 降序排名,保留排名第一的最新支付。
SELECT
order_id,
payment_id,
paid_at,
amount
FROM (
SELECT
order_id,
payment_id,
paid_at,
amount,
ROW_NUMBER() OVER (PARTITION BY order_id ORDER BY paid_at DESC, payment_id DESC) AS rn
FROM fact_payments
WHERE
status = 'paid'
) AS ranked_payments
WHERE
rn = 1
ORDER BY
order_id ASCcompletedGEN—msEXEC212.8069160025916msnull_city_labelcompleted_order_amount_band筛选 2026 年已完成订单,使用 CASE 按订单头 total_amount 分层,并按金额降序、订单号升序输出。
SELECT
order_id,
total_amount,
CASE
WHEN total_amount >= 2000
THEN 'high'
WHEN total_amount >= 1000
THEN 'medium'
ELSE 'low'
END AS amount_band
FROM fact_orders
WHERE
status = 'completed'
AND order_date >= CAST('2026-01-01' AS DATE)
AND order_date < CAST('2027-01-01' AS DATE)
ORDER BY
total_amount DESC,
order_id ASCcompletedGEN—msEXEC251.60224999854108msall_channel_performancesemantic_channel_kpis按 channel_type 分别预聚合完成订单、完成订单行净销售额和支付状态金额,再连接各聚合结果,避免订单行与支付记录直接连接导致重复计算。
WITH channel_types AS (
SELECT DISTINCT
channel_type
FROM dim_channels
), completed_orders AS (
SELECT
c.channel_type,
COUNT(DISTINCT o.order_id) AS completed_order_count
FROM fact_orders AS o
INNER JOIN dim_channels AS c
ON o.channel_id = c.channel_id
WHERE
o.status = 'completed'
GROUP BY
c.channel_type
), net_revenue AS (
SELECT
c.channel_type,
SUM(oi.quantity * oi.unit_price - oi.discount_amount) AS net_revenue
FROM fact_order_items AS oi
INNER JOIN fact_orders AS o
ON oi.order_id = o.order_id
INNER JOIN dim_channels AS c
ON o.channel_id = c.channel_id
WHERE
o.status = 'completed'
GROUP BY
c.channel_type
), payment_amounts AS (
SELECT
c.channel_type,
SUM(CASE WHEN p.status = 'paid' THEN p.amount ELSE CAST(0 AS DECIMAL(14, 2)) END) AS paid_amount,
SUM(CASE WHEN p.status = 'refunded' THEN p.amount ELSE CAST(0 AS DECIMAL(14, 2)) END) AS refunded_amount,
SUM(CASE WHEN p.status = 'failed' THEN p.amount ELSE CAST(0 AS DECIMAL(14, 2)) END) AS failed_amount
FROM fact_payments AS p
INNER JOIN fact_orders AS o
ON p.order_id = o.order_id
INNER JOIN dim_channels AS c
ON o.channel_id = c.channel_id
GROUP BY
c.channel_type
)
SELECT
ct.channel_type,
COALESCE(co.completed_order_count, 0) AS completed_order_count,
COALESCE(nr.net_revenue, CAST(0 AS DECIMAL(14, 2))) AS net_revenue,
COALESCE(pa.paid_amount, CAST(0 AS DECIMAL(14, 2))) AS paid_amount,
COALESCE(pa.refunded_amount, CAST(0 AS DECIMAL(14, 2))) AS refunded_amount,
COALESCE(pa.failed_amount, CAST(0 AS DECIMAL(14, 2))) AS failed_amount
FROM channel_types AS ct
LEFT JOIN completed_orders AS co
ON ct.channel_type = co.channel_type
LEFT JOIN net_revenue AS nr
ON ct.channel_type = nr.channel_type
LEFT JOIN payment_amounts AS pa
ON ct.channel_type = pa.channel_type
ORDER BY
ct.channel_type ASCcompletedGEN—msEXEC592.9132079982082mscategory_revenue_share按商品品类汇总完成订单行的净销售额,再以全部品类净销售额为分母计算百分比占比并四舍五入至 2 位,最后按指定顺序排序。
WITH category_revenue AS (
SELECT
p.category,
SUM(oi.quantity * oi.unit_price - oi.discount_amount) AS net_revenue
FROM fact_orders AS o
INNER JOIN fact_order_items AS oi
ON oi.order_id = o.order_id
INNER JOIN dim_products AS p
ON p.product_id = oi.product_id
WHERE
o.status = 'completed'
GROUP BY
p.category
), category_metrics AS (
SELECT
category,
net_revenue,
ROUND(100.0 * net_revenue / NULLIF(SUM(net_revenue) OVER (), 0), 2) AS revenue_share_pct
FROM category_revenue
)
SELECT
category,
net_revenue,
revenue_share_pct
FROM category_metrics
ORDER BY
revenue_share_pct DESC,
category ASCcompletedGEN—msEXEC210.75562499754597msorder_total_reconciliation汇总每个订单的订单行净额,与订单头 total_amount 在 2 位小数精度下对账,仅输出有差异的订单并按指定顺序排列。
WITH reconciliation AS (
SELECT
o.order_id,
ROUND(o.total_amount, 2) AS stored_total,
ROUND(COALESCE(SUM(oi.quantity * oi.unit_price - oi.discount_amount), 0), 2) AS calculated_total
FROM fact_orders AS o
LEFT JOIN fact_order_items AS oi
ON o.order_id = oi.order_id
GROUP BY
o.order_id,
o.total_amount
), differences AS (
SELECT
order_id,
stored_total,
calculated_total,
ROUND(stored_total - calculated_total, 2) AS difference
FROM reconciliation
WHERE
stored_total <> calculated_total
)
SELECT
order_id,
stored_total,
calculated_total,
difference
FROM differences
ORDER BY
ABS(difference) DESC,
order_id ASCcompletedGEN—msEXEC236.52795900125057ms字段来自运行创建时冻结的快照。
0.1.01181.5.5query-plan-v11.0.030.17.05b5d98876ea35114f18ce6dfa48cc9800d88b6baba80d311b2f52552a38b31afd9058da24c959b3562efdcef6263fa9e5ce1deee644f2ae14ad6853ad3b4d724run-report-v11